Math, asked by nikhil3198, 1 year ago

If tan A = cot B, prove that A + B = 9o degree

Answers

Answered by arvishaali2004

2

By using the concept of complementary angles,

tanA=cot(90-A)

Therefore,

cot(90-A)= cotB (By comparing),

=> 90-A=B

=>A+B=90.....

Hence proved.....

Pls mark my answer as "Brainliest"!!!!!!!

Answered by abdul9838

7

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$\huge \bf \: hola \\ \\ \bf \: hey \: dude \: here \: is \: ans \\ \\ \huge \: solution \\ \\ \bf \: tan \: a = cot \: b \\ \\ \bf \huge \: now \\ \\ \bf \: we \: have \: to \: prove \: a + b = 90 \\ \\ \huge \bf \: given \: that \\ \\ \bf tan \: a = cot \: b \\ \\ \bf \: as \: we \: can \: write \\ \\ \bf \: tan \: a = tan(90° + b) \\ \\ \bf \: a = 90° - b \\ \\ \bf \: a + b = 90° \: \: ans$

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