Question

if tan A + cot equal to 2 then tan square theta + cot square theta equal to ​

Answer 1

Answer:

$\tt \tan ^2 A + \cot ^2 A =2$

Step-by-step explanation:

We have,

$\tt \tan A + \cot A =2$

$\tt (\tan A + \cot A)^2 =4$

Ww know that,

$\boxed{\rm (a+b)^2 =a^2 +b^2 +2ab}$

$\rm \tan ^2 A + \cot ^2 A + 2 \tan A \cot A =4$

$\tt \tan ^2 A + \cot ^2 A + 2 \tan A \bigg(\dfrac{1}{\tan A} \bigg) =4$

$\tt \tan ^2 A + \cot ^2 A + 2 =4$

$\tt \tan ^2 A + \cot ^2 A =4-2$

$\tt \tan ^2 A + \cot ^2 A =2$