If tan A + cot2B = 4, A = 45° and B is an acute angle, then find the value of B.
Answers
Answer:
Given tan2A=cot(A−18
0
)
⇒cot(90−2A)=cot(A−18
0
)[∵tanθ=cot(90−θ)]
Comparing angles we get
90−2A=A−18
⇒90+18=A+2A
⇒3A=108
⇒A=
3
108
⇒A=36
∘
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View Answer
If sin(A−B)=
10
1
,cos(A+B)=
29
2
, fid the value of tan2A where A and B lies between 0 and π/4
the answer is provided in the above attachment.
