If tan a equal to 3 by 4 find 1 by sin a + 1 by cos c
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MATHS
In triangle ABC, right-angled at B, if tanA=
3
1
, find the value of
(i) sinAcosC+cosAsinC
(ii) cosAcosC−sinAsinC
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ANSWER
Given that,
In △ABC,∠B=90
∘
and tanA=
3
1
=tan30
∘
⟹∠A=30
∘
Hence, ∠C=60
∘
(i)sinAcosC+cosAsinC=sin30
∘
cos60
∘
+cos30
∘
sin60
∘
=
2
1
×
2
1
+
2
3
×
2
3
=
4
1
+
4
3
=
4
4
=1
(ii)cosAcosC−sinAsinC=cos30
∘
cos60
∘
−sin30
∘
sin60
∘
=
2
3
×
2
1
−
2
1
×
2
3
=
4
3
−
4
3
=0
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