if tan a is equal to root 3 minus 1 evaluate 10 upon 1 + 10 square A
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Step-by-step explanation:
Given: tanA=√3-1
Tan A÷1+tan square A = √3-1÷1+(√3-1)square
=√3-1÷1+3+1-2√3
( By rationalising the denominator)
=√3-1÷5-2√3×5+2√3÷5+2√3
=(5+2√3)(√3-1)÷(5)square-(2-√3)square
=5√3-5-2√3+6÷25-12
=3√3+1÷13
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