if tan(a)=p/q and tan(b) = q/p then angle(a+b)=
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Answer:
tan(a+b)= (tan a + tan b)/ (1-tan a * tan b) [IDENTITY]
tan(a+b)=(p/q + q/p) / (1 - p/q * q/p)
tan(a+b)=(p/q + q/p) / (1-1)
tan(a+b)=(p/q + q/p) / 0
And division of any number by 0 is not defined so the answer is 'not defined'
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