if tan a = Q Sin b/(p+Q Cos b) then show that tan (a-b)=p sin b/(Q+p cos b)
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AnswertanA=1
tanA=tan45
A=45∘
tanB=3
tanB=tan60
B=60∘
Now, sinAcosB+cosAsinB
= sin(45)cos(60)+cos(45)sin(60)
= 2
1.21+2
1.23
= 22
1+22
3
= 22
1+3
Multiply and divide by 2
= 42
+6
:
Step-by-step explanation:
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