Question

if tan a = Q Sin b/(p+Q Cos b) then show that tan (a-b)=p sin b/(Q+p cos b)​

Answer 1

Answer:

tanA=1

tanA=tan45

A=45∘

tanB=3

​

tanB=tan60

B=60∘

Now, sinAcosB+cosAsinB

= sin(45)cos(60)+cos(45)sin(60)

= 2 ​1​.21​+2​1​.23

​​

= 22 ​1​+22 ​3

​​

= 22 ​1+3

​​

Multiply and divide by 2

​

= 42 +6

​​

Step-by-step explanation:

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