If tan A= Root 3-1 then valur of Tan A/ 1 + tan^2 A is
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Answer:
We have, tanx−tan2x=1..........(1)
Squaring both sides, we get,
tan4x−2tan3x+tan2x=1
⇒tan4x−2tan3x−tan2x+2tanx=1+2tanx−2tan2x
∴tan4x−2tan3x−tan2x+2tanx+1=2+2(tanx−tan2x)=1+2=4 using (1)
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