if tan A = root 3 ,then the value of 2 sec^2A-2 tan^2A .
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Answer:
Value of 2sec²A-2tan²A = 2.
Step-by-step explanation:
Given,
tanA = √3
let,
tanA = √3/1
let,
BC=√3 , AB=1 , AC=?,
According to PHYTHAGAROUS THEROM,
(Hyp)² = (opp.side)² + (adj.side)²
(AC)² = (BC)² + (AB)²
(AC)² = (√3)² + (1)²
(AC)² = 3 + 1
(AC)² = 4
AC = √4
AC = √2×2
:. AC = 2 units
Now consider,
secA = Hyp/adj.side = AC/AB = 2/1
tanA = opp.side/adj.side = BC/AB = √3/1
2sec²A-2tan²A
=> 2(2/1)²-2(√3/1)²
=> 2(4/1)-2(3/1)
=> 2(4) - 2(3)
=> 8 - 6
=> 2
:. 2sec²A-2tan²A = 2.
I hope it helps you!!!
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