If tan A , tan B = 1 , then (A+B) = ?
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Step-by-step explanation:
tan(A+B)tan(A−B)=1⟹
cos(A+B)cos(A−B)−sin(A+B)sin(A−B)==0⟹
cos(A+B+A−B)=0⟹
cos2A=0⟹
2A=π2
tan2A3=tanπ6=13–√
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