Math, asked by rashmi545293, 5 months ago

If tan A = tan B and sin A = m sin B, then prove that  \cos {}^{2} A=  \frac{m {}^{2}  - 1}{n {}^{2} - 1 }

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Answered by Anonymous
21

 \cos {}^{2} A=  \frac{m {}^{2}  - 1}{n {}^{2} - 1 }

Hence, proved.

Please see the above attachment for explanation.

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