Question

if tan ∅= a÷x,then the value of x/√a2+x2 × 15

Answer 1

Answer:

salam guys

Step-by-step explanation:

Trigonometry,

Let's assume @ as theta ok

Given that tan@ = a/x

Therefore, the opposite side is a and the adjacent side x

So the hypotenuse would be root(a²+x²)

so x/root(a²+x²) = adjacent side/hyoptenuse

that's, cos @ .

That's it

Hope it helped mark as BRAINELIEST

Masalam peace

Answer 2

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

$so \: here \: tan \: ∅ = x \div a \: \\ ie \: a = x.tan \: ∅\\ so \: now \: to \: find \: value \: of \: x \div \sqrt{a {}^{2} + x {}^{2} } \\ substituting \: value \: of \: a \: in \: it$

$so \: we \: get \\ x \div \sqrt{x {}^{2} + a {}^{2} } \\ = x \div \sqrt{(x.tan \:∅) {}^{2} + x {}^{2} } \\ = x \div \sqrt{x {}^{2}.tan {}^{2}∅ + x {}^{2} } \\ = x \div \sqrt{x {}^{2} (1 + tan {}^{2}∅) } \\ = x \div \sqrt{x {}^{2} .sec {}^{2}∅} \\ since \: 1 + tan {}^{2} ∅ = sec {}^{2} ∅ \\ \\ taking \: square \: root \: of \: denominator \\ we \: get \\ = x \div x.sec∅ \\ = 1 \div sec \: ∅ \\ = cos \: ∅ \\ since \: 1 \div sec \: ∅ = cos \: ∅$