If tan alfa =1 tan beta =1/7then 2 alfa+ beta =
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TanA = 1
TanB = 1/7
Tan(A+B)=(tanA+tanB)/(1-tanAtanB)
= ( 1 + 1/7 ) / ( 1 - 1/7 )
= 8/7 / 6/7
= 4/3
A + B = tan^-1(4/3)
2 ( A + B) = 2 tan^-1(4/3)
TanB = 1/7
Tan(A+B)=(tanA+tanB)/(1-tanAtanB)
= ( 1 + 1/7 ) / ( 1 - 1/7 )
= 8/7 / 6/7
= 4/3
A + B = tan^-1(4/3)
2 ( A + B) = 2 tan^-1(4/3)
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