If tan alpha = 1/2 and tan beta = 1/3 , then alpha + beta =
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tan(a+b)=(tan a + tan b)/(1-tan a.tan b) =(1/2+1/3)/(1-1/2.1/3) = 1
(5/6)/(1-1/6) (5/6)/(5/6)
a+ b = tan inverse 1
=TT/4
assume alpha in place of a and beta in place of b.
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