Question

if tan alpha =√3 and sin bita =1√2 find alpha + bita​

Answer 1

ANSWER

sinβ=

10

1

Therefore cosβ=

10

10−1

=

10

3

Hence tanβ=

cosβ

sinβ

=

3

1

...(i)

tan2β=

1−tan

2

β

2tanβ

Substituting the value of tanβ from (i) we get

tan2β=

4

3

...(ii)

tanα=

7

1

...(iii)

Now

tan(α+2β)=

1−tanα+tan2β

tanα+tan2β

Substituting the value of tanα and tan2β from iii and ii and by simplifying we get

tan(α+2β)=

28−3

4+21

=1

tan(α+2β)=1

α+2β=45

0

Hence answer is C

I hope you got your answer

Answer 2

Answer:

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