Question

if tan alpha=√3 and tan beta=1/√3. find the value of cot(alpha+beta)??

Answer 1

As, tanα = √3
tanα = tan60
so, α= 60

And, tanβ = 1/√3
tanβ = tan30
so, β = 30

now we have get value of α & β
so, cot(α+β) = cot(60+30)
= cot90
= not defined
because we know that the value of
cot90 is not defined .


I HOPE THIS WILL HELP YOU MY FRIEND

Answer 2

Answer:

Step-by-step explanation:

As, tanα = √3

tanα = tan60

so, α= 60

And, tanβ = 1/√3

tanβ = tan30

so, β = 30

now we have get value of α & β

so, cot(α+β) = cot(60+30)

= cot90

= not defined

because we know that the value of

cot90 is not defined .

I HOPE THIS WILL HELP YOU MY FRIEND