if tan Alpha =√3, find sin alpha.
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√3/2
Step-by-step explanation:
Given, TanA = √3
Then, By using pythagoras theorem we have,
H^2 = P^2 + B^2
= √3^2 + 1^2
H^2 = 3 + 1
H = √4
H = 2
Now, Sin A = P/H = √3 /2 ans....
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