Question

if tan alpha =√3 tan beta =1/√3 find cot ( alpha +beta). when alpha and beta are acute angles

Answer 1

$Heya$‼


I'm writing alpha as @ and beta as ß.


tan @ = √3 ( given )

@ = 60°


tan ß = 1 / √3

ß = 30°



Now, cot ( @ + ß )

= cot ( 60° + 30° )

= cot 90°

= 0

Answer 2

Hope you liked it

Mark as Brainiest...