if tan Alpha equal to 1 by 2 and 10 B equal to 1 by 3 and 10 alpha + beta equal to tan A + tan b 1 upon 1 minus tan a tan B find the value of alpha + beta
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Answer:
tanα=1/2
tanβ=1/3
Now, tan(α+β)=tanα+tanβ/1-tanα.tanβ
=1/2+1/3 / 1- 1/2.1/3
=5/6 / 1- 1/6
=5/6 / 5/6
=1
tan(α+β)=1
(α+β)=45°
Step-by-step explanation:
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