Question

if tan alpha equal to 1by 2 tan beta equal to 1by 3 then (alpha +beta)=
​

Answer 1

tan(a+b)=(tan a + tan b)/(1-tan a.tan b)

=(1/2+1/3)/(1-1/2.1/3)

(5/6)/(1-1/6)

( 5/6)/(5/6)

=1

a+ b = tan inverse 1

=π/4

assume alpha in place of a and beta in place of b

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Answer 2

Answer: tan(a+b)=(tan a + tan b)/(1-tan a.tan b)

=(1/2+1/3)/(1-1/2.1/3)

(5/6)/(1-1/6)

( 5/6)/(5/6)

=1

a+ b = tan inverse 1

=π/4

assume alpha in place of a and beta in place of b