If tan alpha equal to√3 and tan beta =1/√3, 0
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I'm writing alpha as @ and beta as ß.
tan @ = √3 ( given )
@ = 60°
tan ß = 1 / √3
ß = 30°
Now, cot ( @ + ß )
= cot ( 60° + 30° )
= cot 90°
= 0
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