Question

if tan Alpha equal to root 3 and tan beta equal to 1 by root 3 then find the value of cot alpha + beta​

Answer 1

Answer:

Tan A = √3 = Tan 60°

=> A = 60°

Tan B = 1/√3 = Tan 30°

=> B = 30°

cot(A+B) = Cot(60+30) = cot90° = 0 (Ans.)

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Answer 2

Answer:

$\bold\red{Value=0}$

Step-by-step explanation:

Given,

$\tan( \alpha ) = \sqrt{3} \\ \\ = > \cot( \alpha ) = \frac{1}{ \sqrt{3} }$

and,

$\tan( \beta ) = \frac{1}{ \sqrt{3} } \\ \\ = > \cot( \beta ) = \sqrt{3}$

Now,

we know that,

$\cot( \alpha + \beta ) = \frac{ \cot( \alpha ) \cot( \beta ) - 1}{ \cot( \alpha ) + \cot( \beta ) }$

Therefore,

we get,

$= > \cot( \alpha + \beta ) = \frac{( \sqrt{3} \times \frac{1}{ \sqrt{3} }) - 1}{ \sqrt{3} + \frac{1}{ \sqrt{3} } } \\ \\ = \frac{1 - 1}{ \sqrt{3} + \frac{1}{ \sqrt{3} } } \\ \\ = 0$

Hence,

Value = 0