if tan alpha - tan beta =m and cos alpha - cos beta =n then prove that cot (alpha - beta)= 1/m-1/n
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Answer:
your answer........
Step-by-step explanation:
tan(α−β)=
1+tanαtanβ
tanα−tanβ
cot(α−β)=
tanα−tanβ
1+tanαtanβ
....(1)cot(α−β)=
tanα−tanβ
1
+
tanα−tanβ
tanαtanβ
cotα−cotβ=n
tanα
1
−
tanβ
1
=n⇒
tanα−tanβ
1+tanαtanβ
=−
n
1
....(2)
From equation (1) and (2)
cot(α−β)=
m
1
−
n
1
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