If tanθ and cotθ are the roots of the equation x2 + px + q = 0, then the value of q is
Answers
Answer:
x
2
+2x+1=0
⇒(x+1)
2
=0
⇒x=−1
tanθandcotθarerootsoftheequation
sincetanθ=cotθ=−1
ummm!
ans is -5/4
Given : tanθ and cotθ are the roots of the equation x² + px + q = 0,
To Find : the value of q
Solution:
ax² + bx +c = 0
sum of roots = -b/a
product of roots = c/a
x² + px + q = 0,
a = 1 , b = p , c = q
product of roots = q/1 = q
Roots are tanθ and cotθ
Product of roots = tanθ * cotθ
tanθ and cotθ are reciprocal to each other
Hence tanθ * cotθ = 1
Product of roots = 1
=> q = 1
Value of q = 1
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