Question

If tan B +cot B =2, than tan2B+cot2B is :?​

Answer 1

Answer:

We know that 2A=(A+B)+(A−B)

⇒tan2A=tan[(A+B)+(A−B)]

=

1−tan(A+B)tan(A−B)

tan(A+B)+tan(A−B)

using the compound angle formula,

⇒tan(A+B)=

1−tanAtanB

tanA+tanB

=

1−pq

p+q

cot2A=

tan2A

1

=

1−pq

p+q

1

=

p+q

1−pq

∴cot2A=

p+q

1−pq

Answer 2

$4(5) \times 4 = ......$

????

Answer 3

$4(5) \times 4 = ......$

????