If tan[(C-A)/2] = K cot B/2 , find K
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Step-by-step explanation:
ANSWER
We have a[tanA−tan
2
1
(A+B)]
=b[tan
2
1
(A+B)−tanB] .....(1)
or a[
cosAcos
2
1
(A+B)
sinAcos
2
1
(A+B)−cosAsin
2
1
(A+B)
]
=b[
cos
2
1
(A+B)cosB
sin
2
1
(A+B)CosB−cos
2
1
(A+B)sinB
]
or
cosA
ksinAsin
2
1
(A−B)
=
cosB
ksinBsin
2
1
(A−B)
or sin
2
1
(A−B)(
cosA
sinA
−
cosB
sinA
)=0
or sin
2
1
(A−B)(tanA−tanB)=0.
From this equation, we conclude that A=B.
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