if tan(πcosx)=cot(πsinx) then prove that cos(x-π/4)=+-1/2√2
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tan ( π cos x ) = cot ( π sin x )
tan ( π cos x ) = tan [ ±π/2 - π sin x ]
As we know that cot θ = tan ( ±π/2- θ )
π cos x = ±π/2 - π sin x
cos x = ±1/2 - sin x
cos x + sin x = ±1/2
Multiplying both sides by 1/√2
( cos x )1/√2 + ( sin x )1/√2= ± 122√
( cos x )( cos π/4 ) + ( sin x )( sin π/4 ) = ± 1/2√2
cos ( x - π/4 ) = ± 1/2√2
tan ( π cos x ) = tan [ ±π/2 - π sin x ]
As we know that cot θ = tan ( ±π/2- θ )
π cos x = ±π/2 - π sin x
cos x = ±1/2 - sin x
cos x + sin x = ±1/2
Multiplying both sides by 1/√2
( cos x )1/√2 + ( sin x )1/√2= ± 122√
( cos x )( cos π/4 ) + ( sin x )( sin π/4 ) = ± 1/2√2
cos ( x - π/4 ) = ± 1/2√2
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