Question

If tanθ−cotθ=0 find the value of sinθ+cosθ

#Ntse.

Answer 1

tan= cot= 1 at 45°

then sin45+cos 45= 2/√2 =√2

Answer 2

tan θ - cot θ=0

tan θ =cot θ

we know that, tan45=cot45= 1

so θ=45°

sinθ+cosθ

=sin45+cos45

=1/√2+1/√2

=2(1/√2)

=√2

or


tanθ−cotθ=0

tan θ=cot θ

sin θ /cos θ =cos θ / sin θ

sin² θ=cos² θ

sin θ =cos θ

so,sin θ+cos θ

=sin θ+sin θ=2sin θ

=cos θ+cos θ=2cos θ

hope helped !^