If tanθ−cotθ=1, then tan2θ+cot2θ=
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Answer:
We know tanθ=
cotθ
1
,
So, (tanθ+cotθ)
2
=tan
2
θ+cot
2
θ+2
⇒(2)
2
=tan
2
θ+cot
2
θ+2
⇒tan
2
θ+cot
2
θ=2
2
−2
⇒tan
2
θ+cot
2
θ=2
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