Question

If tanθ cotθ= 2 find the value of tan²θ + cot²θ​

Answer 1

Step-by-step explanation:

(tan+ cot)^2=tan^2+2 tancot + cot^2

=tan^2+4+cot^2=(tan+cot)^2

tan^2+cot^2=(tan+cot)^2-4

tan^2+cot^2=(tan-cot)^2

but tan ×cot=1

so please check your question