Question

if tanθ + cotθ = 2, then find the value of tan^2θ + cot^2θ. ​

Answer 1

Answer:

2

Step-by-step explanation:

tan a+cot a =2

tan a + 1/tan a =2

Tan2a + 1 = 2tan a

tan2a -2tan a +1= 0

(tan a +1) 2= 0

tan a +1 = 0

tan a = 1

tan∆2045 + cot20 45 = 1

1∆20+1∆20

1+1

=2