Math, asked by vishukhaire006, 5 hours ago

If tan α + cot α = 2, then tan⁸α + cot⁸α = ​

Answers

Answered by akshrajain30aug2007
2

Answer:

2is the answer

Step-by-step explanation:

the answer is 2

Attachments:
Answered by pulakmath007
2

SOLUTION

GIVEN

\displaystyle \sf{ \tan  \alpha  + \cot  \alpha  = 2}

TO DETERMINE

\displaystyle \sf{ {\tan}^{8}  \alpha + {\cot}^{8}  \alpha  }

EVALUATION

Here it is given that

\displaystyle \sf{ \tan  \alpha  + \cot  \alpha  = 2}

\displaystyle \sf{ \implies \: \tan  \alpha + \frac{1}{\tan  \alpha } = 2}

\displaystyle \sf{ \implies \: \frac{{\tan}^{2}  \alpha + 1}{\tan  \alpha } = 2}

\displaystyle \sf{ \implies \: {\tan}^{2}  \alpha  + 1 = 2\tan  \alpha }

 \displaystyle \sf{ \implies \: {\tan}^{2}  \alpha  + 1 - 2\tan  \alpha  = 0}

\displaystyle \sf{ \implies \: {(\tan  \alpha  - 1)}^{2} = 0}

\displaystyle \sf{ \implies \: (\tan  \alpha  - 1) = 0}

\displaystyle \sf{ \implies \: \tan  \alpha   =  1}

\displaystyle \sf{ \implies \cot  \alpha   =  1}

This gives

\displaystyle \sf{ {\tan}^{8}  \alpha  + {\cot}^{8}  \alpha }

 \displaystyle \sf{ = {1}^{8} + {1}^{8} }

 \sf{ =1 + 1}

 = 2

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