if tan∅+cot∅=3find the value of tan²∅+cot²∅
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Answered by
0
Answer:
we will use ( a + b )² - 2ab
Step-by-step explanation:
( tan Φ + cot Φ ) - 2tanΦ cotΦ
3 - 2 × tanΦ × 1 / tanΦ
3 - 2
1
Answered by
0
Answer:
7
Step-by-step explanation:
tan¢+cot¢=3
sq. both sides,we get
(tan¢+cot¢)^2=(3)^2
tan^2¢+cot^2¢+2tan¢.cot¢=9
tan^2¢+ cot^2¢+2=9 [tan¢.cot¢=1]
tan^2¢+cot^2¢= 9-2=7
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