if tan ∅ +cot∅=5 then find the value of ∅+∅
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Answered by
1
Answer:
The required numeric value of tan^2 A + cot^2 A is 23.
Step-by-step explanation:
It is given that the value of tanA + cotA is 5.
= > tanA + cotA = 5
Square on both sides : -
= > ( tanA + cotA )^2 = 5^2
From the properties of expansions :
( a + b )^2 = a^2 + 2ab + b^2
= > tan^2 A + cot^2 A + 2 tanA cotA = 25
= > tan^2 A + cot^2 A + 2( tanA x 1 / tanA ) = 25
= > tan^2 A + cot^2 A + 2 ( 1 ) = 25
= > tan^2 A + cot^2 A + 2 = 25
= > tan^2 A + cot^2 A = 25 - 2
= > tan^2 A + cot^2 A = 23
Hence,
The required numeric value of tan^2 A + cot^2 A is 23.
Answered by
0
The answer is 23.
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