Question

if tan Q = 4/3 , find the value of sec Q and Cos Q​

Answer 1

Answer:

secQ=5/3 , cosQ=3/5

Step-by-step explanation:

tan Q=4/3

then, perpendicular of the rt. triangle =4k

and base =3k

.'.hypotenuse=√[ (4k)²+(3k)²] = √[16k²+9k²] = √[25k²] = 5k

then, cos Q=3k/5k=3/5

secQ= 5/3

Answer 2

Answer:

sec Q=5/3 cos Q= 3/5

Step-by-step explanation:

1+tan^2theta =sec^2theta

1 +(4/3)^2 =sec^2 theta

1 +16/9 = sec^2 theta

25/9 = sec^2 theta

√25/9 = sec Q

5/3= sec Q

cos Q= 1/sec Q

cos Q= 3/5