Question

If tan + sec 0 = 1, then find the value of sec O.​

Answer 1

Answer:

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Answer 2

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• Given,

• tanθ+secθ=l

• tanθ=l−secθ

• squaring on both sides, we get,

• tan2θ=(l−secθ)2

• sec2θ−1=l2+sec2θ−2lsecθ

• l2−2lsecθ=−1

• l2+1=2lsecθ

• ⇒secθ=2ll2+1

• hope it helps