Question

If tanθ + secθ =2/3


then
tanθ -secθ =​

Answer 1

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We know that

sec²x= 1+tan²x

sec²x-tan²x= 1

(sec x + tan x) (sec x - tan x) = 1

(3) ( sec x - tan x) = 1

(sec x - tan x) = ⅓