Question

. If tanθ + secθ =  2 \3 then tanθ - secθ =??​

Answer 1

Answer:

we know that,

sec²ø-tan²ø=1

(secø+tanø)(secø-tanø)=1

2/3(secø-tanø)=1

-(tanø-secø)=3/2

tanø-secø=-3=2.

Answer 2

Step-by-step explanation:

i hope it is helpful

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