If tan θ + sec θ = l, then prove that sec θ = l^+1/2l
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Abe yaar trignometry hee to nhi aati
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i hope it helps u
Step-by-step explanation:
I = tanФ + secФ
I - secФ = tanФ
l² + sec²Ф - 2 l secФ = tan²Ф
= sec²Ф - 1
So secФ = (l² + 1) / 2l
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