IF (tan +sin ) = m and (tan-sin ) =n prove that(mpower2-npwer2)=16mn
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Step-by-step explanation:
(tanθ+sinθ)=m and (tanθ−sinθ)=n
To prove : (m2−n2)2=165mn
L.H.S=(m2−n2)2
=[(tanθ+sinθ)2−(tanθ−sinθ)2]2
=(4tanθsinθ)2
=16tan2θsin2θ....(1)
R.H.S=16mn
=16(tanθ+sinθ)(tanθ−sinθ)
=16(tan2θ−sin2θ)
=16[sin2θ(cos2θ1−1)]
=16[sin2θ(sec2θ−1)]
=16tan2θsin2θ....(2)
From (1) and (2)
L.H.S=R.H.S
Hope this help you
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