Question

If tanθ+sinθ=m and tanθ-sinθ=n then (m²-n²)²=?​

Answer 1

Answer:

hey here is your solution

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Step-by-step explanation:

so here

tanθ+sinθ=m

and tanθ-sinθ=n

so to find value of (m²-n²)²

substituting values of m and n in it

we get

[(tanθ+sinθ)²-(tanθ-sinθ)²]²

=[(tan²θ+sin²θ+2tan.sinθ)-(tan²θ+sin²-2tan.sinθ)]²

=[(tan²θ+sin²θ+2tan.sinθ-tan²θ-sin²θ+2tan.sinθ)]²

=(2tan.sinθ+2tan.sinθ)²

=(4tan.sinθ)²

=16.sinθ.tanθ