If Tanθ+sinθ=m,tanθ-sinθ=n and m≠n then prove that m²_n²=4√mn
Answers
Answered by
1
Do not fear from question..see what you need to prove and act according... Okk. .prepare the terms you need in prove and in no time you will solve the problem! ! Have Fun
Attachments:
Answered by
0
Let Theta =A
=(tan A+ sin A)²- (tan A - sin A)²
=(tan² A +sin² A +2tanA.sinA-tan² A -sin² A +2tanA.sinA)
=4tanA.sinA
=4√(tan A+sin A)(tan A-sin A)
=4√(tan²A-sin²A)
=4√{(sin²A/cos²A)-sin²A}
=4√{sin²A-sin²A.cos²A}/cos²A
=4√sin²A{1-cos²A}/cos²A
=4√sin²A.sin²A/cos²A
=4 sin²A/cosA
=4 tanA.sinA
LHS = RHS
I hope it's help if you think I am correct please mark brainliest
=(tan A+ sin A)²- (tan A - sin A)²
=(tan² A +sin² A +2tanA.sinA-tan² A -sin² A +2tanA.sinA)
=4tanA.sinA
=4√(tan A+sin A)(tan A-sin A)
=4√(tan²A-sin²A)
=4√{(sin²A/cos²A)-sin²A}
=4√{sin²A-sin²A.cos²A}/cos²A
=4√sin²A{1-cos²A}/cos²A
=4√sin²A.sin²A/cos²A
=4 sin²A/cosA
=4 tanA.sinA
LHS = RHS
I hope it's help if you think I am correct please mark brainliest
Similar questions
Science,
8 months ago
English,
8 months ago
Chemistry,
8 months ago
Psychology,
1 year ago
Geography,
1 year ago