Question

If tanϕ + sinϕ = m, tanϕ − sinϕ = n, Find the value of m2 - n2
2√mn
4√mn
m-n
2mn

Answer 1

tan+ sin = m

tan-sin= n

m2-n2= (tan +sin)2-(tan-sin)2

0-0= 0

2√mn = 2√(tan+sin)*(tan-sin)

2√0*0

2*0=0

4√mn=4√0*0

4*0=0

m-n= tan+sin-tan+sin

0

2mn

2*0=0