Question

if tan sq A=1+2 tan sq B, then cos sq A / cos sq B

Answer 1

Answer:

Step-by-step explanation:

Tan²A = 1 + 2Tan²B

=> Sec²A - 1 = 1 + 2(Sec²B - 1)    

=> Sec²A - 1  = 1 + 2Sec²B - 2

=> Sec²A - 1  = 2Sec²B - 1

=> Sec²A = 2Sec²B

=> 1/Cos²A = 2/Cos²B

=> Cos²A/Cos²B = 1/2

Answer 2

Step-by-step explanation:

here you go thank you