Question

If tan square (3A+15)degree minus 1 =0 then find the value of A that satisfy this condition.

Answer 1

Answer:

A=10°

Step-by-step explanation:

tan ²(3A+15)-1=0

=>tan ²(3A+15)=1

=>tan ²(3A+15)°=tan ²45°

=>3A+15=45

=>3A=30°

=>A=10°