Math, asked by saidev3620, 1 year ago

If tan θ + tan 2θ + √3 tan θ tan 2θ = √3 , then

Answers

Answered by Anonymous
2

Answer:


Step-by-step explanation:

tanθ +tan2θ = √3-√3 tanθtan2θ

tanθ +tan2θ = √3(1-tanθ tan2θ)

tanθ +tan2θ/(1-tanθtan2θ) = √3

tan(θ+2θ) =√3

tan3θ= tan(π/3)

3θ = π/3

θ = π/9

Similar questions