If tan θ + tan 2θ + √3 tan θ tan 2θ = √3 , then
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Step-by-step explanation:
tanθ +tan2θ = √3-√3 tanθtan2θ
tanθ +tan2θ = √3(1-tanθ tan2θ)
tanθ +tan2θ/(1-tanθtan2θ) = √3
tan(θ+2θ) =√3
tan3θ= tan(π/3)
3θ = π/3
θ = π/9
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