if tan teeta is a/b then cos teetha =?
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Tan theta=a/b
Tan^2 theta+1=sec^2 theta
(A^2+b^2÷b^2)1/2=sec theta...
Sec theta=1/cos theta
Cos theta=(b^2÷a^2+b^2)1/2
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hope it helps you✌️✌️
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