Question

if tan tetha - sin² tetha = cos²tetha then show that sin² tetha = ½​

Answer 1

Step-by-step explanation:

Given tanθ=

13

12

cos

2

θ−sin

2

θ

2sinθcosθ

=

cos2θ

sin2θ

=tan2θ=

1−tan

2

θ

2tanθ

=

1−

169

144

2×

13

12

=

169

25

13

24

=

25

24×13

=

25

312

Answer 2

Answer:

$Given tanθ=$ $\frac{12}{13}$

$\frac{2sinθcosθ}{cos^{2}θ-sin^{2} } =\frac{sin2θ​ }{cos2θ}=tan2θ=\frac{2tanθ}{ 1−tanθ}=\frac{2× \frac{12}{13}}{1-\frac{144}{169} } =\frac{\frac{24}{13} }{\frac{25}{169} }=\frac{24*13}{25}=\frac{312}{25}$

 

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