Question

If tan theata =7/8 find value of (1+cos theata )(1-cos theata)/(1+ sin theata )(1-sin theata )

Answer 1

$\frac{1 + \cos(a ) \times 1 - cos(a)}{1 - \sin(a) \times 1 + \sin(a) }$
=
$\frac{ \sin(a) {2} }{ \cos(a) ^{2} }$
=tana^2 =(7/8)^2 =49/64!!!

Answer 2

Hence, 1+cos©/1-cos©×1+sin©/1-sin©=0